Random math problem.
Posted: Sat Apr 24, 2010 8:08 pm
So what is the integral from 0 to 6 of x^2-5 dx?
Working from dusty old math, that's 1/3rd x^3 - 5/2x^2, at the edges.
For 0, that's 0.
For 6, that's 1/3 * 36 * 6 - 5/2 * 36
That simplifies to 36 * 2 - 5 * 18
Or 72 - 90
Or -18
How can the answer be -18? It's been too long; what am I doing wrong on the integral?
Working from dusty old math, that's 1/3rd x^3 - 5/2x^2, at the edges.
For 0, that's 0.
For 6, that's 1/3 * 36 * 6 - 5/2 * 36
That simplifies to 36 * 2 - 5 * 18
Or 72 - 90
Or -18
How can the answer be -18? It's been too long; what am I doing wrong on the integral?